■ TransactionScope 클래스를 사용해 트랜잭션을 설정하는 방법을 보여준다.
▶ Member.cs
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namespace TestProject; /// <summary> /// 회원 /// </summary> public class Member { //////////////////////////////////////////////////////////////////////////////////////////////////// Property ////////////////////////////////////////////////////////////////////////////////////////// Public #region ID - ID /// <summary> /// ID /// </summary> public int ID { get; set; } #endregion #region 성명 - Name /// <summary> /// 성명 /// </summary> public string Name { get; set; } #endregion #region 그룹 ID - GroupID /// <summary> /// 그룹 ID /// </summary> public int? GroupID { get; set; } #endregion } |
▶ Program.cs
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using System; using System.Transactions; using NMemory; using NMemory.Tables; namespace TestProject; /// <summary> /// 프로그램 /// </summary> class Program { //////////////////////////////////////////////////////////////////////////////////////////////////// Method ////////////////////////////////////////////////////////////////////////////////////////// Static //////////////////////////////////////////////////////////////////////////////// Private #region 프로그램 시작하기 - Main() /// <summary> /// 프로그램 시작하기 /// </summary> private static void Main() { Database database = new Database(); Table<Member, int> memberTable = database.Tables.Create<Member, int>(member => member.ID, null); try { using(TransactionScope tran = new TransactionScope()) { memberTable.Insert(new Member() { ID = 1, Name = "김철수" }); memberTable.Insert(new Member() { ID = 2, Name = "홍길동" }); memberTable.Insert(new Member() { ID = 3, Name = "홍삼수" }); memberTable.Insert(new Member() { ID = 4, Name = "김영희" }); memberTable.Insert(new Member() { ID = 5, Name = "이주희" }); //throw new Exception(); tran.Complete(); } } catch { } foreach(Member member in memberTable) { Console.WriteLine($"{member.ID}, {member.Name}"); } } #endregion } |
