[DATABASE/SQLSERVER] 문자열에서 테이블 생성하기

■ 문자열에서 테이블을 생성하는 방법을 보여준다.

▶ 문자열에서 테이블 생성하기 예제 (SQL)


SELECT A.*
FROM   dbo.CreateTable('1,2,3,4,5', ',') AS A;

SELECT A.*

FROM dbo.CreateTable('1,2,3,4,5', ',') AS A;

▶ 문자열에서 테이블 생성하기 (SQL)


CREATE FUNCTION dbo.CreateTableFromString
(
    @P_String    NVARCHAR(MAX) -- 문자열
   ,@P_Separator NVARCHAR(10)  -- 분리자
)
RETURNS @Result TABLE(Item NVARCHAR(100))
AS
BEGIN
    DECLARE @Temp   NVARCHAR(MAX);
    DECLARE @Start  INT;
    DECLARE @End    INT;
    DECLARE @Length INT;
    DECLARE @Index  INT;

    SET @Temp  = ' ' + @P_String;
    SET @Start = 1;
    SET @End   = 0;
    SET @Index = 0;

    WHILE(@Start <> 0)
    BEGIN
        SET @End = CHARINDEX(@P_Separator, @Temp, @Start);

        IF @End <> 0
        BEGIN
            SET @Length = @End - @Start;
        END
        ELSE
        BEGIN
            SET @Length = LEN(@Temp) - @Start + 1;
        END;

        INSERT INTO @Result(Item) VALUES (RTRIM(LTRIM(SUBSTRING(@Temp, @Start, @Length))));

        SET @Start = @End + 1;

        IF @End = 0
        BEGIN
            RETURN;
        END;
    END;

    RETURN;
END

CREATE FUNCTION dbo.CreateTableFromString

(

@P_String NVARCHAR(MAX) -- 문자열

,@P_Separator NVARCHAR(10) -- 분리자

)

RETURNS @Result TABLE(Item NVARCHAR(100))

BEGIN

DECLARE @Temp NVARCHAR(MAX);

DECLARE @Start INT;

DECLARE @End INT;

DECLARE @Length INT;

DECLARE @Index INT;

SET @Temp = ' ' + @P_String;

SET @Start = 1;

SET @End = 0;

SET @Index = 0;

WHILE(@Start <> 0)

BEGIN

SET @End = CHARINDEX(@P_Separator, @Temp, @Start);

IF @End <> 0

BEGIN

SET @Length = @End - @Start;

END

ELSE

BEGIN

SET @Length = LEN(@Temp) - @Start + 1;

END;

INSERT INTO @Result(Item) VALUES (RTRIM(LTRIM(SUBSTRING(@Temp, @Start, @Length))));

SET @Start = @End + 1;

IF @End = 0

BEGIN

RETURN;

END;

RETURN;

END